Advertisements
Advertisements
प्रश्न
A girl of mass 40 kg runs a height of 80 stairs, each 25 cm high with a load of 20 kg on her head in 25 sec. If g is 10 m/s2, find:
(i) Gravitational force acting on the girl.
(ii) Work done by her.
(iii) Useful work done by her.
(iv) Her power in watt.
Advertisements
उत्तर
(i) Gravitational force acting on the girl = Her mass in kg × g
= 40 × 10 = 400 N.
(ii) Total gravitational force = (Mass of girl + load) × g
= (40 + 20) × 10 = 600 N.
and Distance or height =`(80xx25)/100` = 20 m.
∴ Work done by her = 600 N × distance
∴ Total work done = 600 N × 20 m = 12000 J.
(iii) Useful work done = Load × g × Distance covered
= 20 × 10 × 20 = 4000 J.
(iv) Power = `("Total work done")/("Time")=12000/25"W"` = 480 W.
संबंधित प्रश्न
Work done = Force × ........................................
Differentiate between energy and power.
MULTIPLE CHOICE TYPE
In an electric cell which in use, the change in energy is from:
Fill in the blank with suitable word :
Work is measured as a product of __________ and __________
If the work done by a force in moving an object through a distance of 20 cm is 24.2 J, what is the magnitude of the force?
Define Translational motion.
Is power a scalar or a vector quantity?
