Question

A factory produces bulbs. The probability that anyone bulb is defective is `1/50` and they are packed in boxes of 10. From a single box, find the probability that none of the bulbs is defective

Answer 1

Let X be the random variable denoting a bulb to be defective.

Here, n = 10

p = `1/50`

q = `1 - 1/50 = 49/50`

We know that P(X = r) = `""^"n""C"_"r" "p"^"r" "q"^("n" - "r")`

None of the bulbs is defective

i.e., r = 0

P(x = 0) = `""^10"C"_0 (1/50)^0 (49/50)^(10 - 0)`

= `(49/50)^10`