Question

A current of 3 A is passed through a coil of resistance 75 Ω for 2 minutes.

1. How much heat energy is produced?
2. How much charge is passed through the resistance?

Answer 1

Current (I) = 3 A,

Resistance (R) = 75 Ω

Time (t) = 2 min

= 2 × 60

= 120 sec

1. Heat energy w = I²Rt
   = 3² × 75 × 120
   = 9 × 75 × 120
   = 81000 J
2. Charge Q = I × t
   = 3 × 120
   = 360 C