Question

A current of 1 A is drawn by a filament of an electric bulb. What would be the number of electrons passing through the cross-section of the filament in 16 s?

Answer 1

Given:

Current, I = 1 A

Time, t = 16 s

Charge on one electron, e = 1.6 × 10⁻¹⁹ C

Using,

Q = I × t

= 1 × 16

= 16 C

Number of electrons, n = `Q/e`​

= `16/(1.6 xx 10^-19)`

= 10 × 10¹⁹

= 10²⁰

The number of electrons passing through the cross-section of the filament is 10²⁰.