Question

A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is:

पर्याय

• 1.5 A

• 2.0 A

• 2.5 A

• 3.0 A

Answer 1

2.0 A

Explanation:

Taking loop ACDEA

i₁ = 2i₂   ...(i)

−2i₁ + 2i₃ + 4i₃ + 4i₂ = 0

−2i₁ + 6i₃ + 4i₂ = 0

2(−i₁ + 3i₃ + 2i₂) = 0

−i₁ + 3i₃ + 2i₂ = 0

3i₃ + 2i₂ −i₁ = 0   ...(ii)

Solving equations (i) and (ii)

3i₃ + 2i₂ − 3i₂ = 0

3i₃ − i₂ = 0

i₂ = 3i₃    ...(iii)

Taking loop EDFGHE

−3i₂ − 4(i₃ + i₂) + 50 = 0

−3i₂ − 4i₃ − 4i₂ + 50 = 0

7i₂ + 4i₃ = 50 

7(3i₃) + 4i₃ = 50

21i₃ + 4i₃ = 50

25i₃ = 50

i₃ = `50/25`

= 2 A