मराठी

A Company Has Two Plants to Manufacture Bicycles. the First Plant Manufactures 60% of the Bicycles and the Second Plant 40%.

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प्रश्न

A company has two plants to manufacture bicycles. The first plant manufactures 60% of the bicycles and the second plant 40%. Out of the 80% of the bicycles are rated of standard quality at the first plant and 90% of standard quality at the second plant. A bicycle is picked up at random and found to be standard quality. Find the probability that it comes from the second plant.

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उत्तर

Let A, E1 and E2 denote the events that the cycle is of standard quality, plant I is chosen and plant II is chosen, respectively.

\[\therefore P\left( E_1 \right) = \frac{60}{100}\]
\[ P\left( E_2 \right) = \frac{40}{100} \]
\[\text{ Now } , \]
\[P\left( A/ E_1 \right) = \frac{80}{100}\]
\[P\left( A/ E_2 \right) = \frac{90}{100}\]
\[\text{ Using Bayes' theorem, we get} \]
\[\text{ Required probability }  = P\left( E_2 /A \right) = \frac{P\left( E_2 \right)P\left( A/ E_2 \right)}{P\left( E_1 \right)P\left( A/ E_1 \right) + P\left( E_2 \right)P\left( A/ E_2 \right) + P\left( E_3 \right)P\left( A/ E_3 \right)}\]
\[ = \frac{\frac{40}{100} \times \frac{90}{100}}{\frac{60}{100} \times \frac{80}{100} + \frac{40}{100} \times \frac{90}{100}}\]
\[ = \frac{36}{48 + 36} = \frac{36}{84} = \frac{3}{7}\]

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पाठ 30: Probability - Exercise 31.7 [पृष्ठ ९७]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 30 Probability
Exercise 31.7 | Q 17 | पृष्ठ ९७

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(Activity):

Mr. X goes to office by Auto, Car, and train. The probabilities him travelling by these modes are `2/7, 3/7, 2/7` respectively. The chances of him being late to the office are `1/2, 1/4, 1/4` respectively by Auto, Car, and train. On one particular day, he was late to the office. Find the probability that he travelled by car.

Solution: Let A, C and T be the events that Mr. X goes to office by Auto, Car and Train respectively. Let L be event that he is late.

Given that P(A) = `square`, P(C) = `square`

P(T) = `square`

P(L/A) = `1/2`, P(L/C) = `square` P(L/T) = `1/4`

P(L) = P(A ∩ L) + P(C ∩ L) + P(T ∩ L)

`="P"("A")*"P"("L"//"A") + "P"("C")*"P"("L"//"C") + "P"("T")*"P"("L"//"T")`

`= square * square + square * square + square * square`

`= square + square + square`

`= square`

`"P"("C"//"L") = ("P"("L" ∩ "C"))/("P"("L"))`

= `("P"("C") * "P"("L"//"C"))/("P"("L"))`

`= (square * square)/square`

`= square`


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