Question

A child was looking for his father. He went 90 m towards East before turning to his right. Then, he went 20 m before turning to his right again to look for his father at his uncle's place 30 m from this point. His father was not there. Then, he went 100 m to the North before meeting his father in a street. How far from the starting point did the son meet his father?

पर्याय

• 80 m

• 100 m

• 140 m

• 200 m

Answer 1

100 m
Explanation:
According to the question,

AE is the distance between the starting point and the endpoint.
∴ AF = AB - FB
= AB - DC  ...[∵ FB = DC]
= 90 - 30 = 60m
EF = ED - FD  ...[∵ FD = BC]
= ED - BC
= 100 - 20
= 80m
Now,  AE = `sqrt((AF)^2+(EF)^2)`
= `sqrt((60)^2+(80)^2)`
= `sqrt(3600+6400)`
= `sqrt10000= 100`m