Advertisements
Advertisements
प्रश्न
A boy of mass 40 kg runs up a height of 30 steps, each 20 cm high. Find:
(i) The force of gravity acting on the boy.
(ii) The work done by the boy against gravity. (Take g = 9.8 ms−2)
Advertisements
उत्तर
Given : m = 40 kg, g = 9.8 ms−2
Distance moved, d = 30 × 20 cm = 600 cm = 6 m.
(i) The force of gravity, F = mg = 40 × 9.8 = 392 N.
(ii) The work done by the boy, W = F × d = 392 × 6 = 2352 J.
संबंधित प्रश्न
A uniform half meter rule balances horizontally on a knife-edge at 29 cm mark when a weight of 20 gf is suspended from one end
1) Draw a diagram of the arrangement
2) What is the weight of the half meter rule?
At which point is the centre of gravity situated in a circular lamina?
A square cardboard is suspended by passing a pin through a narrow hole at its one corner. Draw a diagram to show its rest position. In the diagram, mark the point of suspension by the letter S and the centre of gravity by the letter G.
Following Fig shows piece of cardboard of uniform thickness cut into different shapes. Draw two lines to indicate the position of centre of gravity G.

A right-angled triangle cardboard piece is placed as shown in fig. 7. Redraw the diagram showing the relative position of the vertices of the triangle when it is suspended by a pin from the hole A. Explain why the position changes?

In ______ equilibrium, the centre of gravity remains at the same height when it is displaced.
Mention the real-life applications of the center of gravity.
In a uniform gravitational field on Earth, the Centre of Gravity and Centre of Mass are:
Why is it beneficial for engineers to design tall structures with a low Centre of Gravity?
