Advertisements
Advertisements
प्रश्न
A boy of mass 30 kg is fitting at a distance of 2 m from the middle of a see-saw. Where should a boy of mass 40 kg sit so as to balance the see-saw?
Advertisements
उत्तर
By the principle of moments 30 × 2 = x × 40
∴ Other boys should sit at a distance
x =`(30xx2)/40`
= 1.5 m
APPEARS IN
संबंधित प्रश्न
In a beam balance, when the beam is balanced in a horizontal position, it is in ______ equilibrium.
The figure shows a uniform metre rule placed on a fulcrum at its mid-point O and having a weight 40 gf at the 10 cm mark and a weight of 20 gf at the 90 cm mark.
- Is the metre rule in equilibrium? If not how will the rule turn?
- How can the rule be brought in equilibrium by using an additional weight of 40 gf?
State two conditions for a body acted upon by several forces to be in equilibrium.
The arms of a beam balance are 20 cm and 21 cm, but the pans are of equal weight. By the method of double weighing the weights are found to be 1000 g and 20 g. Find the actual weight of the body
The moon revolving around the earth is in ______ equilibrium.
What is meant by equilibrium and state the conditions of equilibrium of a body?
What do you mean by dynamic and static equilibrium? Give one example of each.
A ball is placed on a compressed spring. When the spring is released, the ball is observed to fly away.
(i) What form of energy does the compressed spring possess?
(ii) Why does the ball fly away?
How can we increase the stability of an object?
A non uniform beam of weight 120 N pivoted at one end is shown in the diagram below. Calculate the value of F to keep the beam in equilibrium.
