Advertisements
Advertisements
प्रश्न
A body of mass 5 kg falls from a height of 10 m to 4 m. Calculate:
The total energy possessed by the body at any instant? (Take g = 10 ms-2).
Advertisements
उत्तर
The total energy possessed by the body at
any instant remains constant for free-fall
It is equal to the sum of P.E. and K.E
∴ At height 10 m , i.e. at top most point K.E = 0
∴ Total energy = P.E. + K.E.
Total energy = 500 + 0 = 500 J
संबंधित प्रश्न
Fill in the blank
Energy possessed by a compressed spring is ______ energy.
A bucket full of water .is on the first floor of your house and another identical bucket with same quantity of water is kept on the second floor. Which of the two has greater potential energy ?
Differentiate between the potential energy (U) and the kinetic energy (K).
Name three non-renewable sources of energy.
What kind of energy is possessed in a situation when?
A horse running along a level road
What kind of energy is possessed in a situation when?
A stone, in a stretched catapult.
Write the type of energy possessed in the following case:
A moving cricket ball.
A body is thrown vertically upwards. Its velocity keeps on decreasing. What happens to its kinetic energy as its velocity becomes zero?
Use your brain power!
Why do tablets of camphor decrease in size day by day?
