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प्रश्न
A body of mass 5 kg falls from a height of 10 m to 4 m. Calculate:
The total energy possessed by the body at any instant? (Take g = 10 ms-2).
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उत्तर
The total energy possessed by the body at
any instant remains constant for free-fall
It is equal to the sum of P.E. and K.E
∴ At height 10 m , i.e. at top most point K.E = 0
∴ Total energy = P.E. + K.E.
Total energy = 500 + 0 = 500 J
संबंधित प्रश्न
Fill in the blank
An object falling freely from the roof of a multistorey building has ________ and _________ energy when halfway down the building.
Give one relevant example for the following transformation of energy :
Chemical energy to light energy.
Name the type of energy (kinetic energy K or potential energy U) possessed in the given cases:
A compressed spring
What do you understand by the kinetic energy of a body?
Renewable source of energy is:
Name the energy changes for the following:
bicycle brakes
Give one example when:
Electric energy changes to potential energy.
For the same kinetic energy of a body, what should be the change in its velocity if its mass is increased nine times?
The solar cooker is an application of the ______ energy of the sun, while solar cells, solar lamps are applications of the ______ energy of the sun.
Use your brain power!
How do we save fuel by using public transport?
