Advertisements
Advertisements
प्रश्न
A block of wood of mass 24 kg floats on water. The volume of wood is 0.032 m3. Find:
- the volume of block below the surface of water,
- the density of wood.
(Density of water = 1000 kg m−3)
Advertisements
उत्तर
Mass of block of wood = 24 kg
Volume of wood = 0.032 m3
(a) Upthrust = Volume of block below the surface of water (v) × density of liquid × g
Now for floatation , Upthrust = weight of the body = 24 kgf
or , 24 kgf = v × 1000 × g
or , v = `24/1000 = 0.024 "m"^3`
(b) According to the law of floatation,
`"Volume of the submerged block"/"Total volume of block" = "Density of wood"/"Density of water"`
or , `0.024/0.032 = "Density of wood"/1000`
or , Density of wood = `1000 xx 0.024/0.032 = 750 "kgm"^-3`
संबंधित प्रश्न
Complete the following sentence :
An empty tin container with its mouth closed has an average density equal to that of a liquid. The container is taken 2 m below the surface of that liquid and is left there. Then the container will ____________ .
A piece of brass weighs 175 gf in air and 150 gf when fully submerged in water. The density of water is 1.0 g cm-3.
(i) What is the volume of the brass piece? (ii) Why does the brass piece weigh less in water?
What are the units density in (i) C.G.S. and (ii) S.I. system .
A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on water surface?
If the density of ice is 0.9 g cm-3, then what portion of an iceberg will remain below the surface of water in sea? (Density of sea water = 1.1 g cm-3)
A sinker is found to weigh 56.7 gf in water. When the sinker is tied to a cork of weight 6 gf, the combination is found to weigh 40.5 gf in water. Calculate R.D. of cork.
A trawler is fully loaded in sea water to maximum capacity. What will happen to this trawler, if moved to river water? Explain your answer.
Complete the following result:
S.l. unit of density is _________
Complete the following result:
Density in kg m-3 = ______ x density in g cm-3
