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A Block of Mass 2 Kg is Pushed Against a Rough Vertical Wall with a Force of 40 N, Coefficient of Static Friction Being 0.5.

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प्रश्न

A block of mass 2 kg is pushed against a rough vertical wall with a force of 40 N, coefficient of static friction being 0.5. Another horizontal force of 15 N, is applied on the block in a direction parallel to the wall. Will the block move? If yes, in which direction? If no, find the frictional force exerted by the wall on the block.

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उत्तर

Net force on the block `=sqrt(20^2+15^2)-(0.5)xx40`
= 25 - 20 = 5 N

`therefore tantheta =20/15=4/3`

`=> theta=tan^(-1)(4/3)=53^circ`

Therefore, the block will move at 53° angle with the 15 N force.

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पाठ 6: Friction - Exercise [पृष्ठ ९९]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 6 Friction
Exercise | Q 29 | पृष्ठ ९९
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