Advertisements
Advertisements
प्रश्न
A battery of e.m.f. 15 V and internal resistance 2 Ω is connected to two resistors of resistances 4 ohm and 6 ohm joined (a) in series. Find in each case the electrical energy spent per minute in 6 Ω resistor.
Advertisements
उत्तर
Given , E.m.f of battery , V = 15 V
Internal resistance of battery , RB = 2 Ω
Resistance given in circuit , R1 = 4 Ω
R2 = 6 Ω
(i) When resistors are connected in series ,
Equivalent resistance , R = RB + R1 + R2 = 12 Ω
Current in the circuit , I = `15/12` = 1.25 A
Now voltage across resistor R2 , V2 = IR = 1.25 × 6
V2 = 7.50 V
Time , t = 1 min = 60 sec
Energy across R2 , E = `("V"^2"t")/"R" = ((7.5)^2 xx 60)/6`
E = 562.5 J
संबंधित प्रश्न
Compare how an ammeter and a voltmeter are connected in a circuit.
If the current through a floodlamp is 5 A, what charge passed in 10 seconds?
(a) 0.5 C
(b) 2 C
(c) 5 C
(d) 50 C
In the circuit diagram given below five resistances of 10 Ω, 40 Ω, 30 Ω, 20 Ω, and 60 Ω are connected as shown to a 12 V battery.
Calculate:
(a) total resistance in the circuit.
(b) total current flowing in the circuit.
Calculate the effective resistance between the points A and B in the network shown below in Figure 8.45
A bulb of 40 W is used for 12.5 h each day for 30 days. Calculate the electrical energy consumed.
State whether the following statement is True or False:
The SI unit of charge is the coulomb.
What is meant by internal resistance of a cell?
True or False – If False give the correct answer
The representation of the electric current is A
Problems for practice:
If 5A current flows through a circuit, then convert the current in terms of microampere?
