Question

A bag contains 25 tickets, numbered from 1 to 25. A ticket is drawn and then another ticket is drawn without replacement. Find the probability that both tickets will show even numbers.

Answer 1

There are 12 even numbers between 1 to 25.

Consider the given events.
A = An even number ticket in the first draw
B = An even number ticket in the second draw

\[\text{ Now } , \]
\[P\left( A \right) = \frac{12}{25}\]
\[P\left( B/A \right) = \frac{11}{24}\]
\[ \therefore \text{ Required probability } = P\left( A \cap B \right) = P\left( A \right) \times P\left( B/A \right) = \frac{12}{25} \times \frac{11}{24} = \frac{11}{50}\]