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A 50 Kg Girl Wearing High Heel Shoes Balances on a Single Heel. the Heel is Circular with a Diameter 1.0 Cm. What is the Pressure Exerted by the Heel on the Horizontal Floor? - Physics

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प्रश्न

A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?

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उत्तर १

Mass of girl, m = 50 kg

∴Force on the heel, F = mg = 50 x 9.8 = 490 N

Diameter, D = 1.0 cm = `1 xx 10^(-2)m`

`:. "Area A"  =(piD^2)/4 = (3.14xx(1xx10^(-2))^2)/4 = 7.85 xx 10^(-5) m^2`

`:. "Pressure", P = F/A = 490/(7.85xx10^(-5)) = 6.24xx10^6 "Pa"`

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उत्तर २

Mass of the girl, m = 50 kg

Diameter of the heel, d = 1 cm = 0.01 m

Radius of the heel = `r = d/2 = 0.005 m`

Area of the heel = `pir^2`

= π (0.005)2

= 7.85 × 10–5 m2

Force exerted by the heel on the floor:

F = mg

= 50 × 9.8

= 490 N

Pressure exerted by the heel on the floor:

`P = "Force"/"Area"`

`= 490/(7.85xx10^(-5))`

= 6.24 × 106 N m–2

Therefore, the pressure exerted by the heel on the horizontal floor is  6.24 × 106 Nm–2.

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