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प्रश्न
A 150 m long train is moving with constant velocity of 12.5 m/s. Find the equation of the motion of the train
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उत्तर
Length of the train = 150 m
Constant velocity of the train = 12.5 m/s
The equation of motion of the train:
Take time in seconds along the x-axis and distance in meters along the y-axis.
Let the train be at the origin.
∴ Length of the train = 150 m is the negative y-intercept
b = -150
The slope of the motion of the train m = 12.5 m/s
The equation of the line with slope-intercept form is
y = mx + b
∴ y = 12.5x – 150
which is the required equation of motion of the train.
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