Question

A 150 m long train is moving with constant velocity of 12.5 m/s. Find the equation of the motion of the train

Answer 1

Length of the train = 150 m

Constant velocity of the train = 12.5 m/s

The equation of motion of the train:

Take time in seconds along the x-axis and distance in meters along the y-axis.

Let the train be at the origin.

∴ Length of the train = 150 m is the negative y-intercept

b = -150

The slope of the motion of the train m = 12.5 m/s

The equation of the line with slope-intercept form is

y = mx + b

∴ y = 12.5x – 150

which is the required equation of motion of the train.