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A 10 G Bullet with a Charge of 4.00 μC is Fired at a Speed of 270 M S−1 in a Horizontal Direction. a Vertical Magnetic Field of 500 µT Exists in the Space. Find the - Physics

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प्रश्न

A 10 g bullet with a charge of 4.00 μC is fired at a speed of 270 m s−1 in a horizontal direction. A vertical magnetic field of 500 µT exists in the space. Find the deflection of the bullet due to the magnetic field as it travels through 100 m. Make appropriate approximations.

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उत्तर

Given:
Mass of the bullet, m = 10g
Charge of the bullet, q = 4.00 μC
Speed of the bullet in horizontal direction, = 270 m/s
Vertical magnetic field, B = 500 μT
Distance travelled by the bullet, d = 100 m
Magnetic force,
`vecF = q  vecv xx vecB ....(i)`
Also,
F  =  ma
Using equation (i) we can write:
`ma = q vecv xx vecB`

`a = (qvB)/m `
Time taken by the bullet to travel 100 m horizontally,
`t = d/v = 100/270s`
Deflection due to the magnetic field in this time interval,
`y = 1/2at^2`

`= 1/2 xx (4.00 xx 10^-6 xx 270 xx 500 xx 10^-6)/(10xx10^-3) xx (100/270)^2`

= 3.7 × 10 -6 m.

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Force on a Moving Charge in Uniform Magnetic and Electric Fields
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पाठ 12: Magnetic Field - Exercises [पृष्ठ २३०]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 12 Magnetic Field
Exercises | Q 5 | पृष्ठ २३०

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