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(1 + Y + X2 Y) Dx + (X + X3) Dy = 0 - Mathematics

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प्रश्न

(1 + y + x2 y) dx + (x + x3) dy = 0

बेरीज
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उत्तर

\[\left( 1 + y + x^2 y \right)dx + \left( x + x^3 \right)dy = 0\]

\[ \Rightarrow dx + y\left( 1 + x^2 \right)dx + x\left( 1 + x^2 \right)dy = 0\]

\[ \Rightarrow dx + \left( 1 + x^2 \right) \left[ ydx + xdy \right] = 0\]

\[ \Rightarrow \left( 1 + x^2 \right) \left[ ydx + xdy \right] = - dx\]

\[ \Rightarrow \left[ ydx + xdy \right] = - \frac{1}{\left( 1 + x^2 \right)}dx\]

\[ \Rightarrow \left[ ydx + xdy \right] = - \frac{dx}{\left( 1 + x^2 \right)}\]

On integrating both side we get,

\[\left( xy \right) = - \int\frac{1}{1 + x^2}dx\]

\[ \Rightarrow xy = - \tan^{- 1} x + c\]

\[ \Rightarrow xy + \tan^{- 1} x = c\]

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पाठ 22: Differential Equations - Revision Exercise [पृष्ठ १४६]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 22 Differential Equations
Revision Exercise | Q 44 | पृष्ठ १४६

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