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PUC Science कक्षा ११ - Karnataka Board PUC Question Bank Solutions

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Prove that: \[\tan\frac{11\pi}{3} - 2\sin\frac{4\pi}{6} - \frac{3}{4} {cosec}^2 \frac{\pi}{4} + 4 \cos^2 \frac{17\pi}{6} = \frac{3 - 4\sqrt{3}}{2}\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:

\[3\sin\frac{\pi}{6}\sec\frac{\pi}{3} - 4\sin\frac{5\pi}{6}\cot\frac{\pi}{4} = 1\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

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Prove that:
\[\frac{\cos (2\pi + x) cosec (2\pi + x) \tan (\pi/2 + x)}{\sec(\pi/2 + x)\cos x \cot(\pi + x)} = 1\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that

\[\frac{cosec(90^\circ + x) + \cot(450^\circ + x)}{cosec(90^\circ - x) + \tan(180^\circ - x)} + \frac{\tan(180^\circ + x) + \sec(180^\circ - x)}{\tan(360^\circ + x) - \sec( - x)} = 2\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If A = |1, 2, 3, 4, 5|, then the number of proper subsets of A is 

[1] Sets
Chapter: [1] Sets
Concept: undefined >> undefined

In set-builder method the null set is represented by

[1] Sets
Chapter: [1] Sets
Concept: undefined >> undefined

Prove that

\[\frac{\sin(180^\circ + x) \cos(90^\circ + x) \tan(270^\circ - x) \cot(360^\circ - x)}{\sin(360^\circ - x) \cos(360^\circ + x) cosec( - x) \sin(270^\circ + x)} = 1\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that

\[\left\{ 1 + \cot x - \sec\left( \frac{\pi}{2} + x \right) \right\}\left\{ 1 + \cot x + \sec\left( \frac{\pi}{2} + x \right) \right\} = 2\cot x\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that

\[\frac{\tan (90^\circ - x) \sec(180^\circ - x) \sin( - x)}{\sin(180^\circ + x) \cot(360^\circ - x) cosec(90^\circ - x)} = 1\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
\[\sin^2 \frac{\pi}{18} + \sin^2 \frac{\pi}{9} + \sin^2 \frac{7\pi}{18} + \sin^2 \frac{4\pi}{9} = 2\]

 
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
\[\sec\left( \frac{3\pi}{2} - x \right)\sec\left( x - \frac{5\pi}{2} \right) + \tan\left( \frac{5\pi}{2} + x \right)\tan\left( x - \frac{3\pi}{2} \right) = - 1 .\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

In a ∆ABC, prove that:
cos (A + B) + cos C = 0

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

In a ∆ABC, prove that:

\[\cos\left( \frac{A + B}{2} \right) = \sin\frac{C}{2}\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

In a ∆ABC, prove that:

\[\tan\frac{A + B}{2} = \cot\frac{C}{2}\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

In a ∆A, B, C, D be the angles of a cyclic quadrilateral, taken in order, prove that cos(180° − A) + cos (180° + B) + cos (180° + C) − sin (90° + D) = 0

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Find x from the following equations:
\[cosec\left( \frac{\pi}{2} + \theta \right) + x \cos \theta \cot\left( \frac{\pi}{2} + \theta \right) = \sin\left( \frac{\pi}{2} + \theta \right)\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Find x from the following equations:
\[x \cot\left( \frac{\pi}{2} + \theta \right) + \tan\left( \frac{\pi}{2} + \theta \right)\sin \theta + cosec\left( \frac{\pi}{2} + \theta \right) = 0\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
\[\tan 4\pi - \cos\frac{3\pi}{2} - \sin\frac{5\pi}{6}\cos\frac{2\pi}{3} = \frac{1}{4}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
\[\sin\frac{13\pi}{3}\sin\frac{8\pi}{3} + \cos\frac{2\pi}{3}\sin\frac{5\pi}{6} = \frac{1}{2}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
\[\sin \frac{13\pi}{3}\sin\frac{2\pi}{3} + \cos\frac{4\pi}{3}\sin\frac{13\pi}{6} = \frac{1}{2}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined
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