हिंदी

PUC Science कक्षा ११ - Karnataka Board PUC Question Bank Solutions for Mathematics

Advertisements
[object Object]
[object Object]
विषयों
मुख्य विषय
अध्याय
Advertisements
Advertisements
Mathematics
< prev  1141 to 1160 of 3275  next > 

Prove that

\[\frac{\cos 9^\circ + \sin 9^\circ}{\cos 9^\circ - \sin 9^\circ} = \tan 54^\circ\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that

\[\frac{\cos 8^\circ - \sin 8^\circ}{\cos 8^\circ + \sin 8^\circ} = \tan 37^\circ\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Advertisements

Show that one of the following progression is a G.P. Also, find the common ratio in case:

4, −2, 1, −1/2, ...

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Show that one of the following progression is a G.P. Also, find the common ratio in case:

−2/3, −6, −54, ...

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Show that one of the following progression is a G.P. Also, find the common ratio in case:

\[a, \frac{3 a^2}{4}, \frac{9 a^3}{16}, . . .\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Show that one of the following progression is a G.P. Also, find the common ratio in case:1/2, 1/3, 2/9, 4/27, ...

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that:

\[\sin\left( \frac{\pi}{3} - x \right)\cos\left( \frac{\pi}{6} + x \right) + \cos\left( \frac{\pi}{3} - x \right)\sin\left( \frac{\pi}{6} + x \right) = 1\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:

\[\sin\left( \frac{4\pi}{9} + 7 \right)\cos\left( \frac{\pi}{9} + 7 \right) - \cos\left( \frac{4\pi}{9} + 7 \right)\sin\left( \frac{\pi}{9} + 7 \right) = \frac{\sqrt{3}}{2}\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:

\[\sin\left( \frac{3\pi}{8} - 5 \right)\cos\left( \frac{\pi}{8} + 5 \right) + \cos\left( \frac{3\pi}{8} - 5 \right)\sin\left( \frac{\pi}{8} + 5 \right) = 1\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Show that the sequence <an>, defined by an = \[\frac{2}{3^n}\], n ϵ N is a G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that \[\frac{\tan 69^\circ + \tan 66^\circ}{1 - \tan 69^\circ \tan 66^\circ} = - 1\].

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Find:
the ninth term of the G.P. 1, 4, 16, 64, ...

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Find:

the 10th term of the G.P.

\[- \frac{3}{4}, \frac{1}{2}, - \frac{1}{3}, \frac{2}{9}, . . .\]

 

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Find :

the 12th term of the G.P.

\[\frac{1}{a^3 x^3}, ax, a^5 x^5 , . . .\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Find : 

nth term of the G.P.

\[\sqrt{3}, \frac{1}{\sqrt{3}}, \frac{1}{3\sqrt{3}}, . . .\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

 If \[\tan A = \frac{5}{6}\text{ and }\tan B = \frac{1}{11}\], prove that \[A + B = \frac{\pi}{4}\].

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If \[\tan A = \frac{m}{m - 1}\text{ and }\tan B = \frac{1}{2m - 1}\], then prove that \[A - B = \frac{\pi}{4}\].

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Find :

the 10th term of the G.P.

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, . . .\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that:
\[\cos^2 45^\circ - \sin^2 15^\circ = \frac{\sqrt{3}}{4}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined
< prev  1141 to 1160 of 3275  next > 
Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×