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Karnataka Board PUCPUC Science 2nd PUC Class 12

PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions for Mathematics

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The radius of a circle is increasing at the rate of 0.5 cm/sec. Find the rate of increase of its circumference ?

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The side of an equilateral triangle is increasing at the rate of \[\frac{1}{3}\] cm/sec. Find the rate of increase of its perimeter ?

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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Find the surface area of a sphere when its volume is changing at the same rate as its radius ?

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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If the rate of change of volume of a sphere is equal to the rate of change of its radius, find the radius of the sphere ?

[6] Applications of Derivatives
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The amount of pollution content added in air in a city due to x diesel vehicles is given by P(x) = 0.005x3 + 0.02x2 + 30x. Find the marginal increase in pollution content when 3 diesel vehicles are added and write which value is indicated in the above questions ?

[6] Applications of Derivatives
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A ladder, 5 metre long, standing on a horizontal floor, leans against a vertical wall. If the top of the ladder slides down wards at the rate of 10 cm/sec, then find the rate at which the angle between the floor and ladder is decreasing when lower end of ladder is 2 metres from the wall ?

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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If \[V = \frac{4}{3}\pi r^3\] ,  at what rate in cubic units is V increasing when r = 10 and \[\frac{dr}{dt} = 0 . 01\] ?  _________________

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Side of an equilateral triangle expands at the rate of 2 cm/sec. The rate of increase of its area when each side is 10 cm is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The radius of a sphere is changing at the rate of 0.1 cm/sec. The rate of change of its surface area when the radius is 200 cm is

[6] Applications of Derivatives
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A cone whose height is always equal to its diameter is increasing in volume at the rate of 40 cm3/sec. At what rate is the radius increasing when its circular base area is 1 m2?

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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A cylindrical vessel of radius 0.5 m is filled with oil at the rate of 0.25 π m3/minute. The rate at which the surface of the oil is rising, is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The distance moved by the particle in time t is given by x = t3 − 12t2 + 6t + 8. At the instant when its acceleration is zero, the velocity is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The altitude of a cone is 20 cm and its semi-vertical angle is 30°. If the semi-vertical angle is increasing at the rate of 2° per second, then the radius of the base is increasing at the rate of

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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For what values of x is the rate of increase of x3 − 5x2 + 5x + 8 is twice the rate of increase of x ?

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The coordinates of the point on the ellipse 16x2 + 9y2 = 400 where the ordinate decreases at the same rate at which the abscissa increases, are

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The radius of the base of a cone is increasing at the rate of 3 cm/minute and the altitude is decreasing at the rate of 4 cm/minute. The rate of change of lateral surface when the radius = 7 cm and altitude 24 cm is

[6] Applications of Derivatives
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The radius of a sphere is increasing at the rate of 0.2 cm/sec. The rate at which the volume of the sphere increase when radius is 15 cm, is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The volume of a sphere is increasing at 3 cm3/sec. The rate at which the radius increases when radius is 2 cm, is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The distance moved by a particle travelling in straight line in t seconds is given by s = 45t + 11t2 − t3. The time taken by the particle to come to rest is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
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The volume of a sphere is increasing at the rate of 4π cm3/sec. The rate of increase of the radius when the volume is 288 π cm3, is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined
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