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Karnataka Board PUCPUC Science 2nd PUC Class 12

PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions for Mathematics

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Mathematics
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Find the particular solution of the differential equation \[\frac{dy}{dx} = \frac{xy}{x^2 + y^2}\] given that y = 1 when x = 0.

 

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[y' + y = e^x , y\left( 0 \right) = \frac{1}{2}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

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Solve the following initial value problem:-
\[x\frac{dy}{dx} - y = \log x, y\left( 1 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y = e^{- 2x} \sin x, y\left( 0 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[x\frac{dy}{dx} - y = \left( x + 1 \right) e^{- x} , y\left( 1 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\left( 1 + y^2 \right) dx + \left( x - e^{- \tan^{- 1} y} \right) dx = 0, y\left( 0 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} + y \tan x = 2x + x^2 \tan x, y\left( 0 \right) = 1\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:
\[x\frac{dy}{dx} + y = x \cos x + \sin x, y\left( \frac{\pi}{2} \right) = 1\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:
\[\frac{dy}{dx} + y \cot x = 4x\text{ cosec }x, y\left( \frac{\pi}{2} \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y \tan x = \sin x; y = 0\text{ when }x = \frac{\pi}{3}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} - 3y \cot x = \sin 2x; y = 2\text{ when }x = \frac{\pi}{2}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} + y\cot x = 2\cos x, y\left( \frac{\pi}{2} \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[dy = \cos x\left( 2 - y\text{ cosec }x \right)dx\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-
\[\tan x\left( \frac{dy}{dx} \right) = 2x\tan x + x^2 - y; \tan x \neq 0\] given that y = 0 when \[x = \frac{\pi}{2}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

A population grows at the rate of 5% per year. How long does it take for the population to double?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

The rate of growth of a population is proportional to the number present. If the population of a city doubled in the past 25 years, and the present population is 100000, when will the city have a population of 500000?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

In a culture, the bacteria count is 100000. The number is increased by 10% in 2 hours. In how many hours will the count reach 200000, if the rate of growth of bacteria is proportional to the number present?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

If the interest is compounded continuously at 6% per annum, how much worth Rs 1000 will be after 10 years? How long will it take to double Rs 1000?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

The rate of increase in the number of bacteria in a certain bacteria culture is proportional to the number present. Given the number triples in 5 hrs, find how many bacteria will be present after 10 hours. Also find the time necessary for the number of bacteria to be 10 times the number of initial present.

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined
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