Secondary School (English Medium) (5 to 8) कक्षा ८ - CBSE Question Bank Solutions for Mathematics

67² – 37² = (67 – 37) × ______ = ______.

(a + b)(a – b) = a² – b² 

The value of p for 51² – 49² = 100p is 2.

The value of (a + 1)(a – 1)(a² + 1) is a⁴ – 1.

Multiply the following: 

(a² – b²), (a² + b²) 

Using suitable identities, evaluate the following.

9.8 × 10.2

Using suitable identities, evaluate the following.

(35.4)² – (14.6)²

Using suitable identities, evaluate the following.

(69.3)² – (30.7)²

Using suitable identities, evaluate the following.

(9.7)² – (0.3)²

Using suitable identities, evaluate the following.

(132)² – (68)²

Using suitable identities, evaluate the following.

(339)² – (161)²

Using suitable identities, evaluate the following.

(729)² – (271)²

Factorise the following using the identity a² – b² = (a + b)(a – b).

x² – 9

Factorise the following using the identity a² – b² = (a + b)(a – b).

4x² – 25y²

Factorise the following using the identity a² – b² = (a + b)(a – b).

4x² – 49y²

Factorise the following using the identity a² – b² = (a + b)(a – b).

3a²b³ – 27a⁴b

Factorise the following using the identity a² – b² = (a + b)(a – b).

28ay² – 175ax²

Factorise the following using the identity a² – b² = (a + b)(a – b).

9x² – 1

Factorise the following using the identity a² – b² = (a + b)(a – b).

25ax² – 25a

Factorise the following using the identity a² – b² = (a + b)(a – b).

`x^2/9 - y^2/25`