Secondary School (English Medium) (5 to 8) कक्षा ८ - CBSE Question Bank Solutions

Simplify 3x (4x − 5) + 3 and find its values for x = 3.

a (a² + a + 1) + 5 and find its values for

1. a = 0,
2. a = 1,
3. a = − 1.

Work out the following division:

(10x − 25) ÷ 5

Work out the following division:

(10x − 25) ÷ (2x − 5)

Work out the following division:

10y(6y + 21) ÷ 5(2y + 7)

Work out the following division:

9x²y²(3z − 24) ÷ 27xy(z − 8)

Work out the following division:

96abc(3a − 12)(5b − 30) ÷ 144(a − 4) (b − 6)

Divide as directed.

5(2x + 1) (3x + 5) ÷ (2x + 1)

Divide as directed.

26xy(x + 5) (y − 4) ÷ 13x(y − 4)

Divide as directed.

52pqr (p + q) (q + r) (r + p) ÷ 104pq (q + r) (r + p)

Divide as directed.

20(y + 4) (y² + 5y + 3) ÷ 5(y + 4)

Divide as directed.

 x(x + 1) (x + 2) (x + 3) ÷ x(x + 1)

Factorise the expression and divide them as directed.

(y² + 7y + 10) ÷ (y + 5)

Factorise the expression and divide them as directed.

(m² − 14m − 32) ÷ (m + 2)

Factorise the expression and divide them as directed.

(5p² − 25p + 20) ÷ (p − 1)

Factorise the expression and divide them as directed.

4yz(z² + 6z − 16) ÷ 2y(z + 8)

Factorise the expression and divide them as directed.

5pq(p² − q²) ÷ 2p(p + q)

Factorise the expression and divide them as directed.

12xy(9x² − 16y²) ÷ 4xy(3x + 4y)

Factorise the expression and divide them as directed.

39y³(50y² − 98) ÷ 26y²(5y + 7)

The following graph shows the temperature of a patient in a hospital, recorded every hour.

1. What was the patient’s temperature at 1 p.m.?
2. When was the patient’s temperature 38.5°C?
3. The patient’s temperature was the same two times during the period given. What were these two times?
4. What was the temperature at 1.30 p.m.? How did you arrive at your answer?
5. During which periods did the patients’ temperature showed an upward trend?