हिंदी

Science (English Medium) कक्षा १२ - CBSE Question Bank Solutions

Advertisements
विषयों
अध्याय
विषयों
मुख्य विषय
अध्याय

Please select a subject first

Advertisements
Advertisements
< prev  15361 to 15380 of 25615  next > 

Differentiate the function with respect to x. 

cos x . cos 2x . cos 3x

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

`sqrt(((x-1)(x-2))/((x-3)(x-4)(x-5)))`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Advertisements

Differentiate the function with respect to x.

(log x)cos x

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

xx − 2sin x

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

(x + 3)2 . (x + 4)3 . (x + 5)4

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

`(x + 1/x)^x + x^((1+1/x))`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

(log x)x + xlog x

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

`(sin x)^x + sin^(-1) sqrtx`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

xsin x + (sin x)cos x

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

`x^(xcosx) + (x^2 + 1)/(x^2 -1)`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x.

`(x cos x)^x + (x sin x)^(1/x)`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` for the given function:

xy + yx = 1

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` for the given function:

yx = xy

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` for the given function:

(cos x)y = (cos y)x

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` for the given function:

xy = `e^((x - y))`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find the derivative of the function given by f(x) = (1 + x) (1 + x2) (1 + x4) (1 + x8) and hence find f′(1).

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate (x2 – 5x + 8) (x3 + 7x + 9) in three ways mentioned below:

  1. By using the product rule.
  2. By expanding the product to obtain a single polynomial.
  3. By logarithmic differentiation.

Do they all give the same answer?

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If u, v and w are functions of x, then show that `d/dx(u.v.w) = (du)/dx v.w + u. (dv)/dx.w + u.v. (dw)/dx` in two ways-first by repeated application of product rule, second by logarithmic differentiation.

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x:

xx + xa + ax + aa, for some fixed a > 0 and x > 0

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If cos y = x cos (a + y), with cos a ≠ ± 1, prove that `dy/dx = cos^2(a+y)/(sin a)`.

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined
< prev  15361 to 15380 of 25615  next > 
Advertisements
Advertisements
CBSE Science (English Medium) कक्षा १२ Question Bank Solutions
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Biology
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Chemistry
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Computer Science (C++)
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Computer Science (Python)
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ English Core
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ English Elective - NCERT
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Entrepreneurship
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Geography
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Hindi (Core)
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Hindi (Elective)
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ History
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Informatics Practices
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Mathematics
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Physical Education
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Physics
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Political Science
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Psychology
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Sanskrit (Core)
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Sanskrit (Elective)
Question Bank Solutions for CBSE Science (English Medium) कक्षा १२ Sociology
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×