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Arts (English Medium) कक्षा १२ - CBSE Question Bank Solutions for Mathematics

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Mathematics
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x and y are the sides of two squares such that y = x – x2. Find the rate of change of the area of second square with respect to the area of first square.

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

The sides of an equilateral triangle are increasing at the rate of 2 cm/sec. The rate at which the area increases, when side is 10 cm is ______.

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

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A ladder, 5 meter long, standing on a horizontal floor, leans against a vertical wall. If the top of the ladder slides downwards at the rate of 10 cm/sec, then the rate at which the angle between the floor and the ladder is decreasing when lower end of ladder is 2 metres from the wall is ______.

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Let A = { 2, 3, 6 } Which of the following relations on A are reflexive?

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let R be the relation on N defined as by x + 2 y = 8 The domain of R is ____________.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Which of the following is not an equivalence relation on I, the set of integers: x, y

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find the area enclosed by the curve x = 3 cost, y = 2 sint.

[8] Applications of the Integrals
Chapter: [8] Applications of the Integrals
Concept: undefined >> undefined

Find the area of the region included between the parabola y = `(3x^2)/4` and the line 3x – 2y + 12 = 0.

[8] Applications of the Integrals
Chapter: [8] Applications of the Integrals
Concept: undefined >> undefined

R = {(1, 1), (2, 2), (1, 2), (2, 1), (2, 3)} be a relation on A, then R is ____________.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = {1, 2, 3}. Which of the following is not an equivalence relation on A?

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find the area of the region bounded by the curves x = at2 and y = 2at between the ordinate corresponding to t = 1 and t = 2.

[8] Applications of the Integrals
Chapter: [8] Applications of the Integrals
Concept: undefined >> undefined

Let A = {1, 2, 3} and R = {(1, 2), (2, 3), (1, 3)} be a relation on A. Then, R is ____________.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = {1, 2, 3}, then the relation R = {(1, 1), (1, 2), (2, 1)} on A is ____________.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find the area of a minor segment of the circle x2 + y2 = a2 cut off by the line x = `"a"/2`

[8] Applications of the Integrals
Chapter: [8] Applications of the Integrals
Concept: undefined >> undefined

If A is a finite set containing n distinct elements, then the number of relations on A is equal to ____________.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = {1, 2, 3}, then the domain of the relation R = {(1, 1), (2, 3), (2, 1)} defined on A is ____________.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = {1, 2, 3, 4, 5, 6} Which of the following partitions of A correspond to an equivalence relation on A?

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

A relation R on a non – empty set A is an equivalence relation if it is ____________.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Calcualte the area under the curve y = `2sqrt(x)` included between the lines x = 0 and x = 1

[8] Applications of the Integrals
Chapter: [8] Applications of the Integrals
Concept: undefined >> undefined

Draw a rough sketch of the curve y = `sqrt(x - 1)` in the interval [1, 5]. Find the area under the curve and between the lines x = 1 and x = 5.

[8] Applications of the Integrals
Chapter: [8] Applications of the Integrals
Concept: undefined >> undefined
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