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Prove that:
tan 8x − tan 6x − tan 2x = tan 8x tan 6x tan 2x

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
\[\tan\frac{\pi}{12} + \tan\frac{\pi}{6} + \tan\frac{\pi}{12}\tan\frac{\pi}{6} = 1\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

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Prove that:
tan 36° + tan 9° + tan 36° tan 9° = 1

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
tan 13x − tan 9x − tan 4x = tan 13x tan 9x tan 4x

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Find the 4th term from the end of the G.P.

\[\frac{1}{2}, \frac{1}{6}, \frac{1}{18}, \frac{1}{54}, . . . , \frac{1}{4374}\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The fourth term of a G.P. is 27 and the 7th term is 729, find the G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that:
\[\frac{\tan^2 2x - \tan^2 x}{1 - \tan^2 2x \tan^2 x} = \tan 3x \tan x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

The seventh term of a G.P. is 8 times the fourth term and 5th term is 48. Find the G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that sin2 (n + 1) A − sin2 nA = sin (2n + 1) A sin A.

 
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If tan A = x tan B, prove that
\[\frac{\sin \left( A - B \right)}{\sin \left( A + B \right)} = \frac{x - 1}{x + 1}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If tan (A + B) = x and tan (A − B) = y, find the values of tan 2A and tan 2B.

 
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If 5th, 8th and 11th terms of a G.P. are p. q and s respectively, prove that q2 = ps.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If cos A + sin B = m and sin A + cos B = n, prove that 2 sin (A + B) = m2 + n2 − 2.

 
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If tan A + tan B = a and cot A + cot B = b, prove that cot (A + B) \[\frac{1}{a} - \frac{1}{b}\].

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

The 4th term of a G.P. is square of its second term, and the first term is − 3. Find its 7th term.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If x lies in the first quadrant and \[\cos x = \frac{8}{17}\], then prove that:

\[\cos \left( \frac{\pi}{6} + x \right) + \cos \left( \frac{\pi}{4} - x \right) + \cos \left( \frac{2\pi}{3} - x \right) = \left( \frac{\sqrt{3} - 1}{2} + \frac{1}{\sqrt{2}} \right)\frac{23}{17}\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

In a GP the 3rd term is 24 and the 6th term is 192. Find the 10th term.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If tan x + \[\tan \left( x + \frac{\pi}{3} \right) + \tan \left( x + \frac{2\pi}{3} \right) = 3\], then prove that \[\frac{3 \tan x - \tan^3 x}{1 - 3 \tan^2 x} = 1\].

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If a, b, c, d and p are different real numbers such that:
(a2 + b2 + c2) p2 − 2 (ab + bc + cd) p + (b2 + c2 + d2) ≤ 0, then show that a, b, c and d are in G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined
< prev  6621 to 6640 of 13978  next > 
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CBSE Science (English Medium) कक्षा ११ Question Bank Solutions
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