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Solve the equation:

– 4 + (–1) + 2 + 5 + ... + x = 437

[5] Arithmetic Progressions
Chapter: [5] Arithmetic Progressions
Concept: undefined >> undefined

Three numbers in A.P. have the sum of 30. What is its middle term?

[5] Arithmetic Progressions
Chapter: [5] Arithmetic Progressions
Concept: undefined >> undefined

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Find the value of ‘c’ for which the quadratic equation 

(c + 1) x2 - 6(c + 1) x + 3(c + 9) = 0; c ≠ - 1

has real and equal roots.

[4] Quadratic Equations
Chapter: [4] Quadratic Equations
Concept: undefined >> undefined

Solve the following system of linear equations by applying the method of elimination by equating the coefficients

(i)4x – 3y = 4 

2x + 4y = 3

(ii)5x – 6y = 8

3x + 2y = 6

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Solve the following system of linear equations by using the method of elimination by equating the coefficients: 3x + 4y = 25 ; 5x – 6y = – 9

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Solve the following system of equations: 15x + 4y = 61; 4x + 15y = 72

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Solve the following system of equations by using the method of elimination by equating the co-efficients.

`\frac { x }{ y } + \frac { 2y }{ 5 } + 2 = 10; \frac { 2x }{ 7 } – \frac { 5 }{ 2 } + 1 = 9`

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Solve the following system of linear equations by using the method of elimination by equating the coefficients √3x – √2y = √3 = ; √5x – √3y = √2

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Solve for x and y : `\frac { ax }{ b } – \frac { by }{ a } = a + b ; ax – by = 2ab`

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Solve the following system of linear equations :

2(ax – by) + (a + 4b) = 0

2(bx + ay) + (b – 4a) = 0

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Solve (a – b) x + (a + b) y = `a^2 – 2ab – b^2 (a + b) (x + y) = a^2 + b^2`

[3] Pair of Linear Equations in Two Variables
Chapter: [3] Pair of Linear Equations in Two Variables
Concept: undefined >> undefined

Prove the following trigonometric identities:

(i) (1 – sin2θ) sec2θ = 1

(ii) cos2θ (1 + tan2θ) = 1

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

Prove the following trigonometric identities:

`(\text{i})\text{ }\frac{\sin \theta }{1-\cos \theta }=\text{cosec}\theta+\cot \theta `

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

Prove the following identities:

`(i) (sinθ + cosecθ)^2 + (cosθ + secθ)^2 = 7 + tan^2 θ + cot^2 θ`

`(ii) (sinθ + secθ)^2 + (cosθ + cosecθ)^2 = (1 + secθ cosecθ)^2`

`(iii) sec^4 θ– sec^2 θ = tan^4 θ + tan^2 θ`

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

Prove the following identities:

`(i) cos4^4 A – cos^2 A = sin^4 A – sin^2 A`

`(ii) cot^4 A – 1 = cosec^4 A – 2cosec^2 A`

`(iii) sin^6 A + cos^6 A = 1 – 3sin^2 A cos^2 A.`

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

Prove the following identities:

`( i)sin^{2}A/cos^{2}A+\cos^{2}A/sin^{2}A=\frac{1}{sin^{2}Acos^{2}A)-2`

`(ii)\frac{cosA}{1tanA}+\sin^{2}A/(sinAcosA)=\sin A\text{}+\cos A`

`( iii)((1+sin\theta )^{2}+(1sin\theta)^{2})/cos^{2}\theta =2( \frac{1+sin^{2}\theta}{1-sin^{2}\theta } )`

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

Prove the following identities:

`(i) 2 (sin^6 θ + cos^6 θ) –3(sin^4 θ + cos^4 θ) + 1 = 0`

`(ii) (sin^8 θ – cos^8 θ) = (sin^2 θ – cos^2 θ) (1 – 2sin^2 θ cos^2 θ)`

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

If (secA + tanA)(secB + tanB)(secC + tanC) = (secA – tanA)(secB – tanB)(secC – tanC) prove that each of the side is equal to ±1. We have,

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

If tanθ + sinθ = m and tanθ – sinθ = n, show that `m^2 – n^2 = 4\sqrt{mn}.`

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined

If cosθ + sinθ = √2 cosθ, show that cosθ – sinθ = √2 sinθ.

[9] Introduction to Trigonometry
Chapter: [9] Introduction to Trigonometry
Concept: undefined >> undefined
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