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HSC Science (General) १२ वीं कक्षा - Maharashtra State Board Important Questions

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A solution containing 0.73 g of camphor (molar mass 152 g . mol-1) in 36.8 g of acetone (boiling point 56.3°C) boils at 56.55°C. A solution of 0.564 g of unknown compound in the same weight of acetone boils at 56.46oC. Calculate the molar mass of the unknown compound.

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass - Introduction

Define Cryoscopic constant.

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Depression of Freezing Point

Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.

(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.

(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)

Appears in 1 question paper
Chapter: [2] Solutions
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

Which of the following solutions shows maximum depression in freezing point?

(A) 0.5 M Li2SQ4

(B) 1 M NaCl

(C) 0.5 M A12(SO4)3

(D) 0.5 MBaC12

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Depression of Freezing Point

Calculate the mole fraction and molality of HNO3 in solution contaning 12.2%HNO3 (Given atomic mases:H=1, N=13,O=16)

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass - Introduction

Calculate the amount of CaCl2 (van't Hoff factor i = 2.47) dissolved in 2.5 L solution so that its osmotic pressure at 300K is 0.75 atmosphere.

Given : Molar mass of CaCl2 is 111g mol-1

R=0.082 L.atm K-1mol-1

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass - Introduction

Explain, why do aquatic animals prefer to stay at lower level of water during summer?

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Solubility >> Solubility of a Gas in a Liquid

Which of the following is not a colligative property?

Appears in 1 question paper
Chapter: [2] Solutions
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

Which of the following is not a colligative property?

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

Gas (A) is more soluble in water than Gas (B) at the same temperature. Which one of the two gases will have the higher value of KH (Henry’s constant) and why

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Solubility >> Solubility of a Gas in a Liquid

Why do gases always tend to be less soluble in liquids as the temperature is raised?

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Solubility >> Solubility of a Gas in a Liquid

Calculate the amount of CaCl2 (molar mass = 111 g mol−1) which must be added to 500 g of water to lower its freezing point by 2 K, assuming CaCl2 is completely dissociated. (Kf for water = 1.86 K kg mol−1)

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Depression of Freezing Point

A solution of a substance having mass 1.8 x 10-3 kg has the osmotic pressure of 0.52 atm at 280 K. Calculate the molar mass of the substance used.
[Volume = 1 dm3, R = 8.314 J K-1 mol-1]

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass - Introduction

The boiling point of benzene is 353.23 K. When 1.80 gram of non-volatile solute  was dissolved in 90 gram of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of solute.
[Kb for benzene = 2.53 K kg mol-1]

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass - Introduction

An organic substance (M = 169 gram mol–1) is dissolved in 2000 cm3 of water. Its osmotic pressure at 12°C was found to be 0.54 atm. If R = 0.0821 L atm K–1 mol–1, calculate the mass of the solute.

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass - Introduction

Define Freezing point.

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Depression of Freezing Point

The temperature at which vapour pressure of a liquid becomes equal to the atmospheric
pressure is _______.

(A) melting point

(B) boiling point

(C) 273 K

(D) 373 K

 

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Relative Lowering of Vapour Pressure

Which mixture is used for respiration by deep sea divers?

(A) He + O2

(B) Ne + O2

(C) Ar + O2

(D) Kr + O2

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Solubility >> Solubility of a Gas in a Liquid

How does solubility of a gas in water varies with the temperature?

Appears in 1 question paper
Chapter: [2] Solutions and Colligative Properties
Concept: Solubility >> Solubility of a Gas in a Liquid
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