हिंदी
Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

Revision: Trigonometry Mathematics SSLC (English Medium) Class 9 Tamil Nadu Board of Secondary Education

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Formulae [2]

Formula: Trigonometric Ratios

\[sineA=\frac{\text{Perpendicular}}{\text{Hypotenuse}}\]

\[cosineA=\frac{\mathrm{Base}}{\text{Hypotenuse}}\]

\[tangentA=\frac{\text{Perpendicular}}{\mathrm{Base}}\]

\[cotangent A = \frac{\text{Base}}{\text{Perpendicular}}\]

\[secantA=\frac{\text{Hypotenuse}}{\mathrm{Base}}\]

\[cosecantA=\frac{\text{Hypotenuse}}{\text{Perpendicular}}\]

Formula: Trigonometrical Ratios of Complementary Angles

For an acute angle A, 

  1. sin (90° - A) = cos A
  2. cos (90° - A) = sin A
  3. tan (90° - A) = cot A
  4. cot (90° - A) = tan A
  5. sec (90° - A) = cosec A
  6. cosec (90° - A) = sec A

Theorems and Laws [1]

If tan A = cot B, prove that A + B = 90°.

∵ tan A = cot B

tan A = tan (90° – B)

A = 90° – B

A + B = 90°. Proved

Key Points

Key Points: Trigonometric Ratios

For an acute angle A in a right-angled triangle:

  • Hypotenuse is the side opposite the right angle.

  • Perpendicular is the side opposite angle A.

  • Base is the side adjacent to angle A.

Key Points: Trigonometric Ratios of Specific Angles
Angle 30° 45° 60° 90°
sin 0 1/2 1/√2 √3/2 1
cos 1 √3/2 1/√2 1/2 0
tan 0 1/√3 1 √3 Not defined
cosec Not defined 2 √2 2/√3 1
sec 1 2/√3 √2 2 Not defined
cot Not defined √3 1 1/√3 0
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