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Revision: Mensuration >> Area of a Trapezium and a Polygon Maths ICSE ICSE Class 8 CISCE

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Definitions [1]

Area of a circle: The area of a circle is the region occupied by the circle in a two-dimensional plane.

Formulae [7]

Perimeter of a Triangle = 3 × length of a side.

Formula : Perimeter of a Rectangle

Perimeter of a rectangle = 2 × length + 2 × breadth

P = 2(1 + b) ⇒ (i) l = `P/2` − b, i.e., length = `"Perimeter"/2` − breadth

                         (ii) l = `P/2` − l, i.e., breadth = `"Perimeter"/2` − length

Formula: Perimeter of Squares

Perimeter of Square = Total boundary of the square

                                   = Side + Side + Side + Side

P = 4 × Side

Or: P = 4s (where 's' represents the side length)

side = ` "perimeter"/"4"`

Always include the correct linear unit (cm, m, mm, km, etc.)

Area of the trapezium = `1/2` × sum of the lengths of parallel sides × height.

Area of parallelogram = base x height

  • Area of a rhombus = `1/2` x product of lengths of diagonals.

Area of the circle = πr2

Theorems and Laws [1]

If three circles of radius a each, are drawn such that each touches the other two, prove that the area included between them is equal to `4/25 a^2`. [Take `sqrt(3) = 1.73` and π = 3.14.]

When three circles touch each other, their centres form an equilateral triangle, with each side being 2a.

Area of the triangle`=sqrt(3)/4xx2"a"xx2"a" = sqrt(3)"a"^2`

Total area of the three sectors of circles `=3xx60/360xx22/7xx"a"^2 = 1/2xx22/7 "a"^2 = 11/7"a" ^2`

Area of the region between the circles = Area of the triangle - Area of three sectors

`=(sqrt(3)-11/7)"a"^2`

= (1.73 - 1.57)a2

= 0.16 a2

=  0.16 a2

`=4/25"a"^2 `

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