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Revision: Complementary Angles Mathematics (English Medium) ICSE Class 9 CISCE

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Definitions [2]

Complementary angles: When the sum of the measures of two angles is 90°, the angles are called complementary angles. Example, 30° + 60° = 90°.

Complementary angles: When the sum of the measures of two angles is 90°, the angles are called complementary angles. Example, 30° + 60° = 90°.

Formulae [1]

Formula: Trigonometrical Ratios of Complementary Angles

For an acute angle A, 

  1. sin (90° - A) = cos A
  2. cos (90° - A) = sin A
  3. tan (90° - A) = cot A
  4. cot (90° - A) = tan A
  5. sec (90° - A) = cosec A
  6. cosec (90° - A) = sec A

Theorems and Laws [2]

If tan A = cot B, prove that A + B = 90°.

∵ tan A = cot B

tan A = tan (90° – B)

A = 90° – B

A + B = 90°. Proved

Prove that `(tan A)/(cot A) = (sec^2A)/("cosec"^2A)`.

R.H.S. = `(sec^2A)/("cosec"^2A)`

= `(1 + tan^2A)/(1 + cot^2A)`   ...`[(∵ 1 + tan^2A = sec^2A),(1 + cot^2A = "cosec"^2A)]`

= `(1 + (sin^2A)/(cos^2A))/(1 + (cos^2A)/(sin^2A))`

= `((cos^2A  +  sin^2A)/(cos^2A))/((sin^2A  +  cos^2A)/(sin^2A))`

= `(1/(cos^2A))/(1/(sin^2A))`   ...[∵ sin2A + cos2A = 1]

= `(sin^2A)/(cos^2A)`

= tan2A

= tan A . tan A

= `(tan A)/(cot A)`

= L.H.S.

∴ `(tan A)/(cot A) = (sec^2A)/("cosec"^2A)`

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