SSC (English Medium)
SSC (Marathi Semi-English)
Academic Year: 2023-2024
Date & Time: 15th March 2024, 11:00 am
Duration: 2h
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Note -
- All questions are compulsory.
- Use of a calculator is not allowed.
- The numbers to the right of the questions indicate full marks.
- In case of MCQs [Q. No. 1(A)] only the first attempt will be evaluated
and will be given credit. - Draw proper figures wherever necessary.
- The marks of construction should be clear. Do not erase them.
- Diagram is essential for writing the proof of the theorem.
Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:
Out of the dates given below which date constitutes a Pythagorean triplet?
15/8/17
16/8/16
3/5/17
4/9/15
Chapter: [2] Pythagoras Theorem
Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:
sin θ × cosec θ = ______
1
0
`1/2`
`sqrt2`
Chapter: [6] Trigonometry
Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:
Slope of X-axis is ______.
1
−1
0
Cannot be determined
Chapter:
Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:
A circle having radius 3 cm, then the length of its largest chord is ______.
1.5 cm
3 cm
6 cm
9 cm
Chapter:
If ΔABC ∼ ∆PQR and AB : PQ = 2 : 3, then find the value of `(A(triangleABC))/(A(trianglePQR))`.
Chapter:
Two circles of radii 5 cm and 3 cm touch each other externally. Find the distance between their centres.
Chapter:
Find the side of a square whose diagonal is `10sqrt2` cm.
Chapter: [2] Pythagoras Theorem
Angle made by the line with the positive direction of X-axis is given. Find the slope of the line.
45°
Chapter:
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In the above figure, ∠ABC is inscribed in arc ABC.
If ∠ABC = 60°. find m ∠AOC.
Solution:
∠ABC = `1/2` m(arc AXC) ......`square`
60° = `1/2` m(arc AXC)
`square` = m(arc AXC)
But m ∠AOC = \[\boxed{m(arc ....)}\] ......(Property of central angle)
∴ m ∠AOC = `square`
Chapter: [3] Circle
Find the value of sin2θ + cos2θ

Solution:
In Δ ABC, ∠ABC = 90°, ∠C = θ°
AB2 + BC2 = `square` .....(Pythagoras theorem)
Divide both sides by AC2
`"AB"^2/"AC"^2 + "BC"^2/"AC"^2 = "AC"^2/"AC"^2`
∴ `("AB"^2/"AC"^2) + ("BC"^2/"AC"^2) = 1`
But `"AB"/"AC" = square and "BC"/"AC" = square`
∴ `sin^2 theta + cos^2 theta = square`
Chapter: [6] Trigonometry

In the figure given above, `square`ABCD is a square and a circle is inscribed in it. All sides of a square touch the circle. If AB = 14 cm, find the area of shaded region.
Solution:
Area of square = `(square)^2` ......(Formula)
= 142
= `square "cm"^2`
Area of circle = `square` ......(Formula)
= `22/7 xx 7 xx 7`
= 154 cm2
(Area of shaded portion) = (Area of square) - (Area of circle)
= 196 − 154
= `square "cm"^2`
Chapter: [7] Mensuration
The radius of a sector of a circle is 3.5 cm and length of its arc is 2.2 cm. Find the area of the sector.
Chapter:
Find the length of the hypotenuse of a right angled triangle if remaining sides are 9 cm and 12 cm.
Chapter: [2] Pythagoras Theorem
In the given figure, m(arc NS) = 125°, m(arc EF) = 37°, find the measure ∠NMS.

Chapter:
Find the slope of the line passing through the points A(2, 3) and B(4, 7).
Chapter:
Find the surface area of a sphere of radius 7 cm.
Chapter:
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In ΔABC, ray BD bisects ∠ABC, A – D – C, seg DE || side BC, A – E – B, then for showing `("AB")/("BC") = ("AE")/("EB")`, complete the following activity:
Proof :
In ΔABC, ray BD bisects ∠B.
∴ `square/("BC") = ("AD")/("DC")` ...(I) (`square`)
ΔABC, DE || BC
∴ `(square)/("EB") = ("AD")/("DC")` ...(II) (`square`)
∴ `("AB")/square = square/("EB")` ...[from (I) and (II)]
Chapter: [1] Similarity

Given:
Chords AB and CD of a circle with centre P intersect at point E.
To prove:
AE × EB = CE × ED
Construction:
Draw seg AC and seg BD.
Fill in the blanks and complete the proof.
Proof:
In Δ CAE and Δ BDE,
∠AEC ≅ ∠DEB ...`square`
`square` ≅ ∠BDE ...(angles inscribed in the same arc)
∴ ΔCAE ~ ΔBDE ...`square`
∴ `square/ ("DE") = ("CE")/square` ...`square`
∴ AE × EB = CE × ED.
Chapter:
Determine whether the points are collinear.
A(1, −3), B(2, −5), C(−4, 7)
Chapter: [5] Co-ordinate Geometry
∆ABC ~ ∆LMN. In ∆ABC, AB = 5.5 cm, BC = 6 cm, CA = 4.5 cm. Construct ∆ABC and ∆LMN such that `"BC"/"MN" = 5/4`.
Chapter:
In ΔPQR, seg PM is a median, PM = 9 and PQ2 + PR2 = 290. Find the length of QR.
Chapter: [2] Pythagoras Theorem
Prove that, if a line parallel to a side of a triangle intersects the other sides in two district points, then the line divides those sides in proportion.
Chapter:
`1/sin^2θ - 1/cos^2θ - 1/tan^2θ - 1/cot^2θ - 1/sec^2θ - 1/("cosec"^2θ) = -3`, then find the value of θ.
Chapter: [6] Trigonometry
A cylinder of radius 12 cm contains water up to the height 20 cm. A spherical iron ball is dropped into the cylinder and thus water level raised by 6.75 cm. What is the radius of iron ball?
Chapter:
Draw a circle with centre O having radius 3 cm. Draw tangent segments PA and PB through the point P outside the circle such that ∠APB = 70°.
Chapter:
`square`ABCD is trapezium, AB || CD diagonals of trapezium intersects in point P.
Write the answers of the following questions:
- Draw the figure using the given information.
- Write any one pair of alternate angles and opposite angles.
- Write the names of similar triangles with the test of similarity.
Chapter:
AB is a chord of a circle with centre O. AOC is diameter of circle, AT is a tangent at A.
Write answers of the following questions:
- Draw the figure using the given information.
- Find the measures of ∠CAT and ∠ABC with reasons.
- Whether ∠CAT and ∠ABC are congruent? Justify your answer.
Chapter:
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