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प्रश्न
Write the value of `(1 + cot^2 theta ) sin^2 theta`.
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उत्तर
=`(1+ cot^2 theta ) sin ^2 theta`
=` cosec ^2 theta xx 1/ ( cosec^2 theta)`
=1
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Activity: L.H.S. = cotθ + tanθ
= `cosθ/sinθ + square/cosθ`
= `(square + sin^2theta)/(sinθ xx cosθ)`
= `1/(sinθ xx cosθ)` ....... ∵ `square`
= `1/sinθ xx 1/cosθ`
= `square xx secθ`
∴ L.H.S. = R.H.S.
