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प्रश्न
Write the Nernst equation for the cell reaction in the Daniel cell. How will the ECell be affected when concentration of Zn2+ ions is increased?
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उत्तर
Daniell cell
\[\ce{Zn(s) | Zn^{2+} || Cu^{2+} | Cu(s)}\]
Anode: \[\ce{Zn(s) -> Zn^{2+} + 2e^{-}}\]
Cathode: \[\ce{Cu^{2+} + 2e^{-} -> Cu(s)}\]
Cell reaction: \[\ce{Zn(s) + Cu^{2+} <=>> Zn^{2+} + Cu(s)}\]
Q = `([Zn^{2+}])/([Cu^{2+}])`
`E_(Cell) = E_(Cell)^o - 0.059/2 log ([Zn^{2+}])/([Cu^{2+}])`
Above equation shows that the cell potential will decrease with increase in the concentration of \[\ce{Zn^{2+}}\] ion.
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