Advertisements
Advertisements
प्रश्न
Write the logarithmic equation for:
E = `(1)/(2)"m v"^2`
Advertisements
उत्तर
E = `(1)/(2)"m v"^2`
Considering log on both the sides, we get
logE = `"log"(1/2 "m v"^2)`
= `"log"(1)/(2) + "log" "m" + "log" "v"^2`
= log1 - log2 + logm + 2logv
= logm + 2logv - log2.
APPEARS IN
संबंधित प्रश्न
Given 3log x + `1/2`log y = 2, express y in term of x.
If log (a + b) = log a + log b, find a in terms of b.
If log 27 = 1.431, find the value of : log 9
If log (a + 1) = log (4a - 3) - log 3; find a.
Express the following in terms of log 5 and/or log 2: log20
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 75
If 2 log x + 1 = 40, find: log 5x
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log540
If 2 log y - log x - 3 = 0, express x in terms of y.
Find the value of:
`("log"sqrt(27) + "log"8 + "log"sqrt(1000))/("log"120)`
