Advertisements
Advertisements
प्रश्न
If 2 log x + 1 = 40, find: log 5x
Advertisements
उत्तर
2 log x + 1 = 40
⇒ 2log x + log10 = 40
⇒ 2log 10x = 40
⇒ log2 x 5x = 20
⇒ log2 + log5x = 20
⇒ log5x = 20 - log2
⇒ log5x = 20 - 0.3010 ......(Since log2 = 0.3010)
⇒ log5x = 19.6989.
APPEARS IN
संबंधित प्रश्न
If x = (100)a , y = (10000)b and z = (10)c , find log`(10sqrty)/( x^2z^3)` in terms of a, b and c.
If 2 log y - log x - 3 = 0, express x in terms of y.
Express the following in terms of log 2 and log 3: `"log"root(5)(216)`
Express the following in terms of log 2 and log 3: `"log" root(4)(648)`
Write the logarithmic equation for:
V = `(1)/("D"l) sqrt("T"/(pi"r")`
Express the following as a single logarithm:
`(1)/(2)"log"25 - 2"log"3 + "log"36`
Express the following as a single logarithm:
`3"log"(5)/(8) + 2"log"(8)/(15) - (1)/(2)"log"(25)/(81) + 3`
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 75
If 2 log y - log x - 3 = 0, express x in terms of y.
Simplify: log a2 + log a-1
