हिंदी

Write the following rational numbers in pq form. 0⋅6∙

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प्रश्न

Write the following rational numbers in `bb(p/q)` form.

\[\ce{0.\overset{\bullet}{6}}\]

योग
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उत्तर

Let x = 0.666.... = \[\ce{0.\overset{\bullet}{6}}\]

∴ 10x = 6.666... = \[\ce{0.\overset{\bullet}{6}}\]

∴ 10x − x = \[\ce{6.\overset{\bullet}{6} - 0.\overset{\bullet}{6}}\]

∴ 9x = 6

∴ x = `6/9`

∴ x =`2/3` 

∴  \[\ce{0.\overset{\bullet}{6}}\] = `2/3`

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अध्याय 2: Real Numbers - Practice Set 2.1 [पृष्ठ २१]

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बालभारती Mathematics 1 [English] Standard 9 Maharashtra State Board
अध्याय 2 Real Numbers
Practice Set 2.1 | Q 3. (i) | पृष्ठ २१

संबंधित प्रश्न

Add the following rational numbers:

\[- 3 and \frac{3}{5}\]

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\[\frac{- 8}{19} + \frac{- 4}{57}\]

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\[\frac{7}{9} + \frac{3}{- 4}\]

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\[\frac{- 5}{14} - \frac{- 2}{7}\]

Evaluate each of the following:

\[\frac{7}{24} - \frac{19}{36}\]

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\[\frac{3}{4} + \frac{5}{6} + \frac{- 7}{8}\]

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\[\frac{- 7}{4} + 0 + \frac{- 9}{5} + \frac{19}{10} + \frac{11}{14}\]

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\[\left( \frac{13}{7} \times \frac{11}{26} \right) - \left( \frac{- 4}{3} \times \frac{5}{6} \right)\]

Fill in the blanks:

\[\frac{1}{2} \times \left( \frac{3}{4} + \frac{- 5}{12} \right) = \frac{1}{2} \times . . . . . . + . . . . . . \times \frac{- 5}{12}\]

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\[\frac{- 3}{4} \text{by} \frac{9}{- 16}\]

Find (x + y) ÷ (x − y), if

\[x = \frac{2}{7}, y = \frac{4}{3}\]

Find two rational numbers between \[\frac{- 2}{9} \text{and} \frac{5}{9} .\]


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0.3 and -0.5


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Every fraction is a rational number.


0 is the smallest rational number.


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If `p/q` is a rational number, then q cannot be ______.


Every natural number is a rational number but every rational number need not be a natural number.


Put the (✓), wherever applicable

Number Natural
Number
Whole
Number
Integer Fraction Rational
Number
(a) – 114          
(b) `19/27`          
(c) `623/1`          
(d) `-19 3/4`          
(e) `73/71`          
(f) 0          

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