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प्रश्न
Write the equation for the reaction taking place between 1, 2-dibromoethane and alcoholic potassium hydroxide.
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उत्तर
\[\begin{array}{cc}
\ce{CH2 - CH2 + 2KOH -> 2KBr + \underset{Acetylene}{CH ≡ CH} + 2H2O}\\
|\phantom{.......}|\phantom{............................................}\\
\ce{\underset{1, 2-dibromoethane}{Br\phantom{.....}Br}}\phantom{...........................................}\\
\end{array}\]
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\[\begin{array}{cc}
\phantom{......}\ce{H}\phantom{..}\ce{H}\phantom{..}\ce{H}\phantom{........}\\
\phantom{}|\phantom{...}|\phantom{...}|\phantom{..}\\
\ce{H-C-C-C-OH}\\
\phantom{}|\phantom{...}|\phantom{...}|\phantom{..}\\
\phantom{......}\ce{H}\phantom{..}\ce{H}\phantom{..}\ce{H}\phantom{........}\\
\end{array}\]
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