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प्रश्न
Write the equation for the reaction taking place between 1, 2-dibromoethane and alcoholic potassium hydroxide.
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उत्तर
\[\begin{array}{cc}
\ce{CH2 - CH2 + 2KOH -> 2KBr + \underset{Acetylene}{CH ≡ CH} + 2H2O}\\
|\phantom{.......}|\phantom{............................................}\\
\ce{\underset{1, 2-dibromoethane}{Br\phantom{.....}Br}}\phantom{...........................................}\\
\end{array}\]
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\[\begin{array}{cc}
\phantom{.}\ce{H\phantom{...}H\phantom{...}O}\phantom{..}\\
\phantom{.}|\phantom{....}|\phantom{....}||\phantom{..}\\
\ce{H - C - C - C - OH}\\
\phantom{}|\phantom{....}|\phantom{......}\\
\phantom{}\ce{H\phantom{...}H}\phantom{......}
\end{array}\]
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