Question

Write a C++ program to find the smallest of five given integers using the min() function to return the smallest of five given integers.

Answer 1

#include 
<iostream.4> int min 9int, cint, int, int, int);
main()
{
    int a, b, c, d, c, small;
    cout<<"Enter the five nos",
    in>>a>>b>>c>>d>>c;
    small = min(a, b, c, d, c);
    cout<<in The smallest No is
    = "<<small;
    return(0)
}
    int min (int nt, inf n2,
    in n3, int n4, inf n5)
{
    int low;
    low = nt
    if (n2<low)
    low = n2;
    if (n3<low)
    low = n3;
    if (n4<low)
    low = n4;
    if (n5<low)
    low = n5;
    return (low);
}

• The min() function (from <algorithm>) compares two values and returns the smaller one.
• Since min() works with two values at a time, we nest the function calls to compare all five numbers.
• The final result is stored in the variable smallest.

Example

Input: 10 25 3 40 18

Output: Smallest number is: 3