हिंदी

Work Function of Aluminium is 4.2 Ev. If Two Photons Each of Energy 2.5 Ev Are Incident on Its Surface, Will the Emission of Electrons Take Place? Justify Your Answer. - Physics

Advertisements
Advertisements

प्रश्न

Work function of aluminium is 4.2 eV. If two photons each of energy 2.5 eV are incident on its surface, will  the emission of electrons take place? Justify your answer. 

टिप्पणी लिखिए
Advertisements

उत्तर

Φ0 = 4.2 eV 

hv = 2.5 eV

No there will not be emission of electron because photoelectric effect is one photon are electron
phenomenon.
The energy of one photon is less than walk function. So there will be no emission.

shaalaa.com
Photoelectric Effect and Wave Theory of Light
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2018-2019 (March) 55/3/3

संबंधित प्रश्न

The threshold frequency for a certain metal is 3.3 × 1014 Hz. If light of frequency 8.2 × 1014 Hz is incident on the metal, predict the cut-off voltage for the photoelectric emission.


Light of frequency 7.21 × 1014 Hz is incident on a metal surface. Electrons with a maximum speed of 6.0 × 105 m/s are ejected from the surface. What is the threshold frequency for photoemission of electrons?


If light of wavelength 412.5 nm is incident on each of the metals given below, which ones will show photoelectric emission and why?

Metal Work Function (eV)
Na 1.92
K 2.15
Ca 3.20
Mo 4.17

A photographic film is coated with a silver bromide layer. When light falls on this film, silver bromide molecules dissociate and the film records the light there. A minimum of 0.6 eV is needed to dissociate a silver bromide molecule. Find the maximum wavelength of light that can be recorded by the film.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


A horizontal cesium plate (φ = 1.9 eV) is moved vertically downward at a constant speed v in a room full of radiation of wavelength 250 nm and above. What should be the minimum value of v so that the vertically-upward component of velocity is non-positive for each photoelectron?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


In the arrangement shown in the figure, y = 1.0 mm, d = 0.24 mm and D = 1.2 m. The work function of the material of the emitter is 2.2 eV. Find the stopping potential V needed to stop the photocurrent.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


The electromagnetic theory of light failed to explain ______.


Cathode rays can be deflected by


In photoelectric effect, the photoelectric current


An increase in the intensity of the radiation causing photo-electric emission from a surface does not affect the maximum K.E. of the photoelectrons. Explain.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×