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प्रश्न
Without solving, comment upon the nature of roots of the following equation:
`x^2 + 2sqrt(3)x - 9 = 0`
योग
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उत्तर
`x^2 + 2sqrt(3)x - 9 = 0`
a = 1, b = `2sqrt(3)` and c = −9
∴ Discriminant (Δ) = b2 – 4ac
= `(2sqrt3)^2 - 4(1) (-9)`
= 4 × 3 + 36
= 12 + 36
= 48
Since D = 48 and 48 > 0.
The roots are real and distinct.
Since 48 is not a perfect square, its roots are irrational.
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