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प्रश्न
Without distance formula, show that the points P(2,1), Q(-1,-5), R(1,5) and S(-2,-1) form a parallelogram.
योग
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उत्तर
Slope of PQ = `(-5 - 1)/(-1 -2)` = 2
Slope of RS = `(5 + 1)/(1 + 2)` = 2
Slope of PQ = Slope of RS
`therefore` PQ ll RS
Also,slope of QR = `(5 + 5)/(1 + 1) = 5`
Slope of SP = `(-1 - 19)/(-2 -2) = 5`
Slope of QR = Slope of SP
`therefore` QR ll SP
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