Question

With vertices A, B and C of ΔABC as centres, arcs are drawn with radii 14 cm and the three portions of the triangle so obtained are removed. Find the total area removed from the triangle.

Answer 1

Total area removed = `(∠A)/360 πr^2 + (∠B)/360 πr^2 + (∠C)/360 πr^2`

= `(∠A + ∠B + ∠C)/360 πr^2`

= `180/360 πr^2`

= `180/360 xx 22/7 xx (14)^2`

= 308 cm²