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Why vital force theory was discarded?

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प्रश्न

Why vital force theory was discarded?

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उत्तर

Vital force theory was discarded because Friedrich Wöhler showed that it was possible to obtain an organic compound (urea) in the laboratory.

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अध्याय 12: Organic Chemistry - Intext Questions [पृष्ठ १८७]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 12 Organic Chemistry
Intext Questions | Q 1. (b) (ii) | पृष्ठ १८७

संबंधित प्रश्न

Draw the structural formula for Diethyl ether


How will you convert
Ethyne to ethane


Write the composition of the following:

 Methylated spirit


State what do you observe ethene is bubbled through a solution of bromine in terachloromethane (carbon tetrachloride)


Write down the equation for the preparation of ethyne from calcium carbide?

The list of some organic compounds is given below:
Ethanol, ethane, methane, ethyne and ethene
From the above list, name a compound:

Which has vapour density 14 and turns acidic potassium permanganate colourless?


Which compound should be heated with soda lime to obtain ethane gas in the laboratory?


Give balanced equation for the laboratory preparations of the following organic compound:

An unsaturated hydrocarbon from calcium carbide


Give the structural formulae of the following :

Ethanoic acid


The structures of six organic compounds are shown:

A

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C = C - C - H}\\
|\phantom{.............}|\\
\ce{H}\phantom{............}\ce{H}
\end{array}\]

B

\[\begin{array}{cc}
\phantom{.......}\ce{H}\phantom{.....}\ce{O}\\
\phantom{.......}|\phantom{.....}//\\
\ce{H - C - C}\\
\phantom{......}|\phantom{.....}\backslash\\
\phantom{...........}\ce{H}\phantom{.....}\ce{O - H}
\end{array}\]

C

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

D

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{O}\\
\phantom{.......}\backslash\\
\phantom{.........}\ce{H}
\end{array}\]

E

\[\begin{array}{cc}
\ce{H}\\
|\\
\ce{H - C - H}\\
\ce{H}\phantom{....}\phantom{....}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

F

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{C = C}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}
\end{array}\]

  1. Identify two of the compounds that are members of the same homologous series but are not isomers.
  2. Which two compounds are isomers of each other?
  3. F can be prepared from D. Give a chemical equation for the reaction.

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