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Which term of the progression 4 + 8 + 12 + ... is 76? - Mathematics

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प्रश्न

Which term of the progression 4 + 8 + 12 + ... is 76?

योग
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उत्तर

a = 4

d = 8 − 4

d = 4

an = 76

an = a + (n − 1)d

76 = 4 + (n − 1)4

76 = 4 + 4n − 4

76 = 4n

n = `76/4`

n = 19

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अध्याय 9: Arithmetic and geometric progression - Exercise 9B [पृष्ठ १८०]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 9 Arithmetic and geometric progression
Exercise 9B | Q 3. (a) | पृष्ठ १८०
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