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प्रश्न
Which term of the A.P. `1, 1 1/6, 1 1/3`, ......, is 3?
योग
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उत्तर
The terms are $$1, \frac{7}{6}, \frac{4}{3}$$.
Here $$a = 1$$ and $$d = \frac{7}{6} - 1 = \frac{1}{6}$$.
Let the term be nth.
$$1 + (n - 1) \times \frac{1}{6} = 3$$
So $$\frac{n + 5}{6} = 3$$, giving $$n = 13$$.
Hence 3 is the 13th term.
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