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प्रश्न
Which of the points P(0, 3), Q(1, 0), R(0, –1), S(–5, 0), T(1, 2) do not lie on the x-axis?
विकल्प
P and R only
Q and S only
P, R and T
Q, S and T
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उत्तर
P, R and T
Explanation:
As we know, if a point is of the form (x, 0) i.e., its y-coordinate is zero, then it will lie on x-axis otherwise not. Here, y-coordinates of points P(0, 3), R(0, –1) and T(1, 2) are not zero, so these points do not lie on the x-axis.
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संबंधित प्रश्न
Find the ratio in which the point (2, y) divides the line segment joining the points A (-2,2) and B (3, 7). Also, find the value of y.
Prove that (4, 3), (6, 4) (5, 6) and (3, 5) are the angular points of a square.
If A(3, y) is equidistant from points P(8, −3) and Q(7, 6), find the value of y and find the distance AQ.
What is the distance between the points (5 sin 60°, 0) and (0, 5 sin 30°)?
The ratio in which the x-axis divides the segment joining (3, 6) and (12, −3) is
In Fig. 14.46, the area of ΔABC (in square units) is
In the above figure, seg PA, seg QB and RC are perpendicular to seg AC. From the information given in the figure, prove that: `1/x + 1/y = 1/z`
If the points P(1, 2), Q(0, 0) and R(x, y) are collinear, then find the relation between x and y.
Given points are P(1, 2), Q(0, 0) and R(x, y).
The given points are collinear, so the area of the triangle formed by them is `square`.
∴ `1/2 |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)| = square`
`1/2 |1(square) + 0(square) + x(square)| = square`
`square + square + square` = 0
`square + square` = 0
`square = square`
Hence, the relation between x and y is `square`.
Assertion (A): The ratio in which the line segment joining (2, -3) and (5, 6) internally divided by x-axis is 1:2.
Reason (R): as formula for the internal division is `((mx_2 + nx_1)/(m + n) , (my_2 + ny_1)/(m + n))`
The distance of the point (3, 5) from x-axis (in units) is ______.
